时间:2008-05-12 13:48:54   来源:论坛整理  作者:  编辑:chinaitzhe

#include <iostream>
#include <string>
using std::cout;
using std::cin;
using std::endl;
using std::string;

int main() {

string text; // The string to be sorted
const string separators = " ,.!:;\ "\?\n\t "; // Word delimiters

// Read the string to be searched from the keyboard
cout < < endl < < "Enter a string terminated by #: " < < endl;
std::getline(cin, text, '# ');

// Count the words in the text
size_t start = text.find_first_not_of(separators); // Word start index
size_t end = 0; // End delimiter index
int word_count = 0; // Count of words stored

while(start != string::npos) {
end = text.find_first_of(separators, start 1);
if(end == string::npos) // Found a separator?
end = text.length(); // No, so set to last 1
word_count ; // Increment count

// Find the first character of the next word
start = text.find_first_not_of(separators, end 1);
}

// Allocate an array of pointers to strings in the free store
string** pwords = new string*[word_count];

start = text.find_first_not_of(separators); // Word start index
end = 0; // End delimiter index
int index = 0; // Current array index

while(start != string::npos) {
end = text.find_first_of(separators, start 1);
if(end == string::npos) // Found a separator?
end = text.length(); // No, so set to last 1
pwords[index ] = new string(text.substr(start, end - start)); // Store the word

// Find the first character of the next word
start = text.find_first_not_of(separators, end 1);
}

// Sort the words in ascending sequence using the array of pointers
int lowest = 0; // Index of lowest word

for(int j = 0; j < word_count - 1 ; j ) {
lowest = j; // Set lowest

// Check current against all the following words
for(int i = j 1 ; i < word_count ; i )
if(*pwords[i] < *pwords[lowest]) // Current is lower?
lowest = i;

if(lowest != j) { // Then swap pointers
string* ptemp = pwords[j]; // Save current
pwords[j] = pwords[lowest]; // Store lower in current
pwords[lowest] = ptemp; // Restore current
}
}

// Output up to six words to a line in groups starting with the same letter
char ch = (*pwords[0])[0]; // First letter of first word
int words_in_line = 0; // Words in a line count
for(int i = 0; i < word_count ; i ) {
if(ch != (*pwords[i])[0]) { // New first letter?
cout < < endl; // Start a new line
ch = (*pwords[i])[0]; // Save the new first letter
words_in_line = 0; // Reset words in line count
}
cout < < *pwords[i] < < " ";
if( words_in_line == 6) { // Every sixth word
cout < < endl; // Start a new line
words_in_line = 0;
}
}

// Delete words from free store
for(int i = 0 ; i < word_count ; i )
delete pwords[i];

// Now delete the array of pointers
delete [] pwords;

cout < < endl;
return 0;
}


我编译这段代码会出现for语句里的i变量重复定义的错误--- 'i ' : redefinition; multiple initialization
这是怎么回事啊大哥大姐们？
网友回复:编译器不支持新C＋＋标准

在别的循环中不用i就是的，改成k,l,m,n...随你
网友回复:换VC8
网友回复:把int去掉吧
网友回复:扔了你的破VC6吧，用它学C 就是浪费生命。
换VC2005，devcpp
网友回复:真的是编译器问题
换成VC2005就不会有这样的问题了吗？
网友回复:把int i 提取出来定义就可以了
网友回复:你把变量声明定义移到for循环外面
网友回复:例：
for(int i=0;i <10;i )
{
for(int i=0;i <10;i )
{
cout < <"*";
}
cout < <endl;
}

用VC6编译不通过，但VC2005就可以通过，C 标准是答应这样的代码的。